Marketplace
Related Categories
- Study
- Studies
- Diploma
- Case Study
- Scholarships
- Education
- Middle School
- High School
- College
- Degree
- Lesson Plans
- Worksheets
- Comprehension
- Learning
- Teaching
- University
Recently Added
- High School Diplomas
- Case Study On Entrepreneurship
- Sample Case Study
- College Distance Learning
- Math Worksheets 5th Grade
- Free Lesson Plans And Worksheets
- Water Cycle Lesson Plans
- Dementia Case Studies
- Free Ged Diploma Online
- The Times University Guide 2011
- Colleges And Universities In California
- Periyar University Distance Education
- Preparing To Teach In The Lifelong Learning Sector
- Accredited Distance Learning
- Help In Reading Comprehension
- Visual Arts Lesson Plans
- University Of London
- Leading University With
- Leading Universities Of The World
- Victoria University Tafe Courses
Join StudyUp.com Today
You Recently Visited
Linear Equations Worksheets
Jacqueline Said:
Please help me solve these linear equations using substitution!?We Answered:
x = y - 43x + y = 12
Substitute x with y - 4 in the second equation.
3x + y = 12
3(y - 4) + y = 12
Distribute.
3(y) + 3(-4) + y = 12
3y - 12 + y = 12
4y - 12 = 12
Add 12 to both sides.
4y - 12 + 12 = 12 + 12
4y = 24
Divide both sides by 4.
4y / 4 = 24 / 4
y = 6
Plug this into the first equation to find x.
x = y - 4
x = 6 - 4
x = 2
ANSWER: (2, 6)
~~~~~~~~~~~~~~~~~~~~~~~
y - 5 = x
4x - y = 4
Substitute x with y - 5 in the second equation.
4x - y = 4
4(y - 5) - y = 4
Distribute.
4(y) + 4(-5) - y = 4
4y - 20 - y = 4
3y - 20 = 4
Add 20 to both sides.
3y - 20 + 20 = 4 + 20
3y = 24
Divide both sides by 3.
3y / 3 = 24 / 3
y = 8
Plug this into the first equation to find x.
y - 5 = x
8 - 5 = x
3 = x
ANSWER: (3, 8)
~~~~~~~~~~~~~~~~~~~~~~~
y - 2x = -6
5x - y = 9
Solve the first equation for y.
y - 2x + 2x = -6 + 2x
y = 2x - 6
Substitute y with 2x - 6 in the second equation.
5x - y = 9
5x - (2x - 6) = 9
Distribute.
5x - (2x) - (-6) = 9
5x - 2x + 6 = 9
3x + 6 = 9
Subtract 6 from both sides.
3x + 6 - 6 = 9 - 6
3x = 3
Divide both sides by 3.
3x / 3 = 3 / 3
x = 1
Plug this into the modified first equation.
y = 2x - 6
y = 2(1) - 6
y = 2 - 6
y = -4
ANSWER: (1, -4)
~~~~~~~~~~~~~~~~~~~~~~~
3y + x = 2
y = x - 6
Substitute y with x - 6 in the first equation.
3y + x = 2
3(x - 6) + x = 2
Distribute.
3(x) + 3(-6) + x = 2
3x - 18 + x = 2
4x - 18 = 2
Add 18 to both sides.
4x - 18 + 18 = 2 + 18
4x = 20
Divide both sides by 4.
4x / 4 = 20 / 4
x = 5
Plug this into the second equation to find y.
y = x - 6
y = 5 - 6
y = -1
ANSWER: (5, -1)
John Said:
worksheets to graphically identify approximate solutions to systems of two linear equations.?We Answered:
I'm not sure that you need any specific worksheet except for graph paper. If you're just looking for a way to approximate the solution of a system of equations, just graph the two lines and find the point of intersection. For easier problems, th intersection will be an easy point - at (1, 3) or at (-5, 2) for example. Otherwise, the intersection will be somewhere fractional, and you'll have to approximate the answers as (1.5, 3.5) for example.Monica Said:
What does the graph of a system of linear equations look like if the product of the slopes of the lines is -1?We Answered:
They will be perpendicular to each other...if one line has a slope of 3 then the other has a slope of -1/3....this is also a condition to check if 2 lines a perpendicular...the product of the slopes HAS to be =to -1 if they are to be perpendicular...On the other hand if they are parallel their slopes are equal...
Fred Said:
Simple Algebra Need Help: Writing Linear Equations?We Answered:
x-intercept 4 means (4, 0) is the point.y-intercept - 2 means (0, - 2) is the point.
Calculate slope m = rise/run
m = (- 2 - 0)/(0 - 4) = - 2/(- 4) = 1/2
Using slope-intercept form y = mx + b
y = (1/2)x - 2
Jeffery Said:
linear equations in two variables? y = x - 5?We Answered:
your question isn't complete. what are you supposed to do wth the equation?