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Six Grade Math Worksheets
Virgil Said:
College Prep Math help please!!!?We Answered:
36 is three dozen so if you buy 3 dozen at $1.42 a dozen, it costs $1.42 times 3 = $4.26. But if you bought each pack separately at $0.15 each, it costs 36 times ).15 = $5.40So do 5.40 - 4.26 to see how much you save.
Bryan Said:
Please help with an odd math problem?We Answered:
I'm not sure if there are other answers, but the way I would solve this is to first note that the 363 cubes were not exterior on any side. Since it is rectangular, and noting that 363 is 121*3, then one way to do it is to lay out the three rows of 121, then surround them with cubes on *all* sides, including the ends. So, the outside top would be 5 cubes across, bottom the same, sides each three, and ends 9 cubes total - be careful to not count any cubes twice!So, to put it all together, 121*5*2(for top and bottom) + 121*2(for two sides, but can't count the ones already there for the top and bottom) + 9*2(each end cap, none have been previously counted) + 363(inside ones) = total volume
I think I did that correctly, but check it over to make sure I didn't mess up somewhere!
Gertrude Said:
Do you think my teachers give too much homework?We Answered:
By any measure that seems too much. Certainly no ten year old should have enough to keep them up that late. Somewhere along the line, people (teachers, school districts and parents) have decided that the measure of a good education is how much work that you have to do outside of school. This is unlikely to change unless you can get your parents and the PTA working with the school to change policies.Have a look online for the case against homework and The Homework Myth - both good books that argue that too much homework actually decreases student motivation and achievement
Nathan Said:
Please help with an odd math problem?We Answered:
Hi,The 363 nonpainted cubes form a rectangular prism themselves. 363 can factor into 3 x 11 x 11, so this inner rectangular prism is 3 by 11 by 11. With the painted blocks added on each side, the entire prism is 5 x 13 x 13. The volume of the 5 x 13 x 13 prism is 845 cubic units.
The number 363 can also factor into 1 x 3 x 121, so this inner rectangular prism could be 1 by 3 by 121. With the painted blocks added on each side, the entire prism is 3 x 5 x 123. The volume of the 3 x 5 x 123 prism is 1,845 cubic units.
The number 363 can also factor into 1 x 11 x 33, so this inner rectangular prism could be 1 by 11 by 33. With the painted blocks added on each side, the entire prism is 3 x 13 x 35. The volume of the 3 x 13 x 35 prism is 1,365 cubic units.
The number 363 can also factor into 1 x 1 x 363, so this inner rectangular prism could be 1 by 1 by 363. With the painted blocks added on each side, the entire prism is 3 x 3 x 365. The volume of the 3 x 3 x 365 prism is 3,285 cubic units.
So, there is more than one correct answer possible.
I hope that helps!! :-)
Priscilla Said:
I need some math help, please?We Answered:
1) How many different ways can 36 identical chairs be placed in rows if all rows have the same number of chairs, each chair is in exactly one row, and no row has more than 20 chairs or less than 3 chair?The question is a factorization in disguise: find the integers by which 36 can be diveded:
2, 3, 4, 6, 9, 12 and 18
There should be more than 3 chairs per row. So that leaves five options to do so. (We assume that the question indeed means rowS.)
2) How many square feet are in the area of a rectangular chalkboard whose width is 4 feet and the diagonal length is 10 feet? Round to the nearest tenth of a square foot.
Rectangular board with given dimensions, combined with Pythagoras:
4^2 + x^2 = 10^2
--> 16 + x^2 = 100
--> x^2 = 100 - 16
--> x = 9.165
Area of the board = 4 * 9.165 = 36.7
3) What is the probability of drawing a card from those pictured where the letter is the first letter of a month of the year? Express your answer as a common fraction.
****The pictures are just A B C D E in a rectangle
Cards with pictures are: A(ce) K(ing) Q(ueen) and J(ack). 4 cards each.
Only A and J are starting letters of months.There are 4 Aces and 4 Jacks in a deck of 16 (picture) cards. Therefor the answer is 8/16 = 1/2.
4) The number 15 can be written as the sum of 2 or 3 consecutive integers. What is the positive difference between the product of the set of 2 numbers and the product of the set of 3 numbers?
15 as sum of 2 consecutive integers? 7 + 8 (product of 7 and 8 = 56)
15 as sum of 3 consecutive integers? 4 + 5 + 6 (product of 4, 5 and 6 = 120)
Answer: 120 - 56 = 64
5) What is the maximum number of triangles that can be formed if two congruent squares are overlapped?
8. And you need squares that are quite similar in size!
6) A school has 7 periods a day. Six are 48 minutes in length and one is 1 hour. The school day starts at 7:35 AM and ends at 2:13 PM with 4 minutes passing time between periods and one-half hour for lunch. What percent of the school day is spent in class? Round your answer to the nearest whole percent?
School is from 7:35 to 14.13. That is: 6 hours and 38 minutes or 398 minutes in total.
Six periods of 48 minutes plus one of 60 minutes = 6 * 48 + 60 = 288 + 60 = 348.
348/398 = 87 % classtime (of total schooltime)
7) There are two two-digit perfect squares whose square roots are the same as their units digits. What is the sum of these squares?
This needs some more text to answer. What perfect square are they refering to? What units digits?
8) Evaluate: 2+ 4(3)-5
??? What's this notation ???
9) A dart randomly hits a dartboard that is composed of concentric squares whose sides are x, y, and z, where x<y<z. In terms of x, y, and z, what is the probability that a dart will land inside the second largest square but outside the smallest square?
The assignment implies that the dart will always be within the biggest square (z, with area z^2). Chance that dart will land inside z and y, but outside x?
Chance the dart will land outside y: (z^2-y^2)/z^2
Chance the dart will land inside y: 1 - (z^2-y^2)/z^2
Chance the dart will land inside x: x^2/z^2
Chance the dart will land outside x: 1-(x^2/z^2)
So the answer is: (1-(x^2/z^2)) * (1 - (z^2-y^2)/z^2)